# -*- coding: utf-8 -*-
"""
Created on Thu Dec 18 10:50:10 2014

@author: grivet

Exercice 5-1d : Résolution d'une équation non-linéaire
par la méthode de Newton
"""

import numpy as np

TOL = 1E-6
def  fn(x):
    return x - 0.2*np.sin(x) - 0.5
def dfndx(x):
    return 1 - 0.2*np.cos(x)

x = float(input("valeur initiale: ")) 
print("\t x \t      fn(x) \t      dfndx")
while abs( fn(x)) > TOL:
    print( "%12.6f \t %12.6f\t %12.6f\n" %(x,fn(x),dfndx(x)))
    x =  x - fn(x)/dfndx(x)